select top 1 id,FolderName,mid(classbasicinfo,instr(classbasicinfo,"||||")+4) as s,mid(s,1,instr(s,"||||")-1) as 栏目简介,mid(classbasicinfo,1,instr(classbasicinfo,"||||")-1) as 栏目图片 from ks_class where classid={$Param(0)}

不过有字数限制,在论坛里搜搜,有个更复杂的方法 修改函数标签的方法